How do you graph $y = - \frac{1}{4} tan 8 π x$ $y=-1/4tan8pix$ ?

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Answer 1 · 2018-07-11T01:27:35

As Below.

Standard form of tangent function is $y = A tan (B x - C) + D$ $y = A tan (Bx - C) + D$

$Given : y = - (\frac{1}{4}) tan (8 π x)$ $"Given : " y = -(1/4) tan (8pi x)$

$A = - \frac{1}{4}, B = 8 π, C = D = 0$ $A = -1/4, B = 8 pi, C = D = 0$

$A m p l i t u d e = | A | = NONE for tangent function$ $Amplitude = |A| = "NONE for tangent function"$

$Period = \frac{π}{| B |} = \frac{π}{8 π} = \frac{1}{8}$ $"Period " = pi / |B| = (pi)/(8pi) = 1/8$

$Phase Shift = - \frac{C}{B} = 0, No Phase Shift$ $"Phase Shift " = -C / B = 0, " No Phase Shift"$ #

$Vertical Shift = D = 0, No Vertical Shift$ $"Vertical Shift " = D = 0, " No Vertical Shift"$

graph{-(1/4) tan(8 pi x) [-10, 10, -5, 5]}

How do you graph y=-1/4tan8pixy=−14tan8πxy=-1/4tan8pix?