How do you graph #y =1/x^2#?

1 Answer
Jul 16, 2015

The graph of this function looks like a bell centred around the y axis.

Explanation:

First you must ensure that the denominator is different from zero so you set:
#x!=0#

The y axis becomes a vertical asymptote of your function; basically the graph of your function will be a curve that gets as near as possible to the y axis without ever crossing it.

When #x# gets near zero (but not zero!) the function becomes very big positively (try with #x=0.001# you get #y=1/0.001^2=1,000,000) while when #x# becomes very large (positively or negatively) the function tends to become very small (try with #x=100# you get: #y=1/100^2=0.0001#).
So your graph will look like:
graph{1/x^2 [-10, 10, -5, 5]}

This function is particularly interesting when describing the phenomenon of Resonance in physics!