How do you graph #y= 12+2x# using intercepts?

1 Answer
Gió
Jan 28, 2016

Try this:

Explanation:

We start from the #x-"intercept"# by setting #y=0#, so we get:
#0=12+2x#
#x=-12/2=-6#
so:
#x-#intercept at: #(-6,0)#

Then we find the #y-"intercept"# by setting #x=0#, so we get:
#y=12#
so:
#y-#intercept at: #(0,12)#

Graphically:
enter image source here

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