How do you graph $y = 12 + 2 x$ $y= 12+2x$ using intercepts?

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How do you graph $y = 12 + 2 x$ $y= 12+2x$ using intercepts?

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Answer 1 · 2016-01-28T13:05:53

Try this:

Explanation:

We start from the $x - intercept$ $x-"intercept"$ by setting $y = 0$ $y=0$ , so we get:
$0 = 12 + 2 x$ $0=12+2x$
$x = - \frac{12}{2} = - 6$ $x=-12/2=-6$
so:
$x -$ $x-$ intercept at: $(- 6, 0)$ $(-6,0)$

Then we find the $y - intercept$ $y-"intercept"$ by setting $x = 0$ $x=0$ , so we get:
$y = 12$ $y=12$
so:
$y -$ $y-$ intercept at: $(0, 12)$ $(0,12)$

Graphically:
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How do you graph $y = 12 + 2 x$ $y= 12+2x$ using intercepts?

1 Answer

Explanation:

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Science

Math

Humanities

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How do you graph y=12+2xy= 12+2x using intercepts?

1 Answer

Explanation:

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Impact of this question

How do you graph $y = 12 + 2 x$ $y= 12+2x$ using intercepts?