How do you graph #y=15/(x^2+2)# using asymptotes, intercepts, end behavior?
1 Answer
Jan 15, 2018
See below.
Explanation:
Vertical asymptotes occur where the function is undefined.i.e.
There are no real solutions to this, so no vertical asymptotes.
As
As
So, x axis is a horizontal asymptote.
( This is also the end behaviour ).
Maximum value occurs when:
This is when
GRAPH:
graph{15/(x^2+2) [-18.02, 18.01, -9.01, 9]}