How do you graph $y = - 2 - 3 sin (x - π)$ $y=-2 - 3 sin (x - pi)$ ?

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How do you graph $y = - 2 - 3 sin (x - π)$ $y=-2 - 3 sin (x - pi)$ ?

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Answer 1 · 2016-11-18T04:45:21

See the inserted graph and the explanation.

Explanation:

$y = - 2 - 3 sin (x - π) = - 2 + 3 sin (π - x) = - 2 + 3 sin x$ $y=-2-3 sin (x-pi)=-2+3 sin (pi-x)=-2+ 3 sin x$

The period $2 π$ $2pi$ for sin x is the period of y..

The graph is symmetrical about (0. -2).

So, a Table for the half period $x \in [0, π]$ $x in [0, pi]$ is sufficient for extending

it for one period $x \in [- π . π]$ $x in [-pi. pi]$ .

$(x, y) : (0, - 2) (\frac{π}{6}, - \frac{3}{2}) (\frac{π}{3}, 3 \frac{\sqrt{3}}{2} - 2) (\frac{π}{2}, 1)$ $(x, y): (0, -2) (pi/6, -3/2) (pi/3, 3sqrt3/2-2) (pi/2, 1)$

$(\frac{2}{3} π, 3 \frac{\sqrt{3}}{2}) (\frac{5}{6} π, = \frac{3}{2}) (π, - 2)$ $(2/3pi, 3sqrt3/2) (5/6pi, =3/2) (pi, -2)$

The crests of f the periodic wave in the graph are at

$(- \frac{3}{2} π, 1), (\frac{π}{2}, 1) and (\frac{5}{2} π, 1)$ $(-3/2pi, 1), (pi/2, 1) and (5/2pi, 1)$ .

graph{y=3 sinx -2 [-10, 10, -5, 5]}

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How do you graph $y = - 2 - 3 sin (x - π)$ $y=-2 - 3 sin (x - pi)$ ?

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