How do you graph #y-2=3(x+5)#?

1 Answer
Feb 4, 2015

First of all, let's do some manipulations: expanding the product on the right side, we get
#y-2=3x+15#
Adding 2 at both sides:
#y=3x+17#
Now we have expressed the line in the standard form #y=ax+b#. To draw a line, you need to have two point which surely belong to the line, and then connect them. Let's choose two easy points: for #x=0# we have #y=17#, so the point #(0,17)# belongs to the line. If #x=-5#, we have #y=-15+17=2#, so the point #(-5,2)# also belongs to the line. Now, you just need to draw them on the plain and then connect them. Here's the graph:
graph{y=3x+17 [-23.1, 28.2, -9.25, 16.42]}