How do you graph $y = 2 + 3 x$ $y=2+3x$ ?

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Answer 1 · 2018-07-10T14:03:21

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$y = 2 + (3 \cdot 0)$ $y = 2 + (3 * 0)$

$y = 2 + 0$ $y = 2 + 0$

$y = 2$ $y = 2$ or $(0, 2)$ $(0, 2)$

Second Point: For $x = 1$ $x = 1$

$y = 2 + (3 \cdot 1)$ $y = 2 + (3 * 1)$

$y = 2 + 3$ $y = 2 + 3$

$y = 5$ $y = 5$ or $(1, 5)$ $(1, 5)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-2)^2-0.075)((x-1)^2+(y-5)^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y-2-3x)(x^2+(y-2)^2-0.075)((x-1)^2+(y-5)^2-0.075)=0 [-20, 20, -10, 10]}

How do you graph y=2+3xy=2+3x?