How do you graph $y = - \frac{2}{3} x + 4$ $y= -2/3x +4$ by plotting points?

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Answer 1 · 2018-03-10T16:53:36

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$y = (- \frac{2}{3} \cdot 0) + 4$ $y = (-2/3 * 0) + 4$

$y = 0 + 4$ $y = 0 + 4$

$y = 4$ $y = 4$ or $(0, 4)$ $(0, 4)$

Second Point: For $x = 3$ $x = 3$

$y = (- \frac{2}{3} \cdot 3) + 4$ $y = (-2/3 * 3) + 4$

$y = - 2 + 4$ $y = -2 + 4$

$y = 2$ $y = 2$ or $(3, 2)$ $(3, 2)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-4)^2-0.04)((x-3)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y + (2/3)x-4)(x^2+(y-4)^2-0.04)((x-3)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}

How do you graph y=−23x+4y= -2/3x +4 by plotting points?