How do you graph $y = 2 {sin}^{- 1} (2 x)$ $y = 2\sin^{-1}(2x)$ ?

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Answer 1 · 2014-11-06T22:55:22

Step 1: Sketch the graph of $y = {sin}^{- 1} x$ $y=sin^{-1}x$ .

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Step 2: Horizontally shrink the graph in Step 1 by a factor of $2$ $2$ .

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Step 3: Vertically shretch the graph in Step 2 by a factor of $2$ $2$ .

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The graph in blue above is the graph of $y = 2 {sin}^{- 1} (2 x)$ $y=2sin^{-1}(2x)$ .

I hope that this was helpful.

How do you graph y=2sin−1(2x)y = 2\sin^{-1}(2x)?