How do you graph #y = 2\sin^{-1}(2x)#?

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Answer 1 · 2014-11-06T22:55:22

Step 1: Sketch the graph of #y=sin^{-1}x#.

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Step 2: Horizontally shrink the graph in Step 1 by a factor of #2#.

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Step 3: Vertically shretch the graph in Step 2 by a factor of #2#.

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The graph in blue above is the graph of #y=2sin^{-1}(2x)#.

I hope that this was helpful.