How do you graph $y = 2 sec (3 (x - \frac{π}{6})) + 1$ $y=2sec(3(x-pi/6))+1$ ?

Question

How do you graph $y = 2 sec (3 (x - \frac{π}{6})) + 1$ $y=2sec(3(x-pi/6))+1$ ?

1 Answer

Impact of this question

3390 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-24T02:58:39

As below.

Explanation:

$y = 2 sec (3 x - \frac{π}{2})$ $y = 2 sec (3x - pi/2)$

Standard form of secant function is $y = A sec (B x - C) + D$ $y = A sec(Bx - C) + D$

$A = 2, B = 3, C = - \frac{π}{2}, D = 1$ $A = 2, B = 3, C = -pi/2, D = 1$

$A m p l i t u d e = | A | = NONE for secant function$ $Amplitude = |A| = "NONE for secant function"$

$Period = \frac{2 π}{| B |} = \frac{2 π}{3}$ $"Period " = (2pi) / |B| = (2pi) / 3$

$Phase Shift = - \frac{C}{B} = \frac{\frac{π}{2}}{3} = \frac{π}{6}, \frac{π}{6} to the RIGHT$ $"Phase Shift " = -C / B = (pi/2) / 3 = pi/6, " " pi/6 " to the RIGHT"$

$Vertical Shift = D = 1$ $"Vertical Shift " = D = 1$

graph{2 sec(3x - pi/2) + 1 [-10, 10, -5, 5]}

Science

Math

Humanities

... and beyond

How do you graph $y = 2 sec (3 (x - \frac{π}{6})) + 1$ $y=2sec(3(x-pi/6))+1$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you graph y=2sec(3(x−π6))+1y=2sec(3(x-pi/6))+1?

1 Answer

Explanation:

Related questions

Impact of this question

How do you graph $y = 2 sec (3 (x - \frac{π}{6})) + 1$ $y=2sec(3(x-pi/6))+1$ ?