How do you graph $y = - 2 x + 3$ $y= -2x+3$ ?

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Answer 1 · 2018-06-15T12:57:42

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$y = (- 2 \cdot 0) + 3$ $y = (-2 * 0) + 3$

$y = 0 + 3$ $y = 0 + 3$

$y = 3$ $y = 3$ or $(0, 3)$ $(0, 3)$

First Point: For $x = 2$ $x = 2$

$y = (- 2 \cdot 2) + 3$ $y = (-2 * 2) + 3$

$y = - 4 + 3$ $y = -4 + 3$

$y = - 1$ $y = -1$ or $(2, - 1)$ $(2, -1)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-3)^2-0.035)((x-2)^2+(y+1)^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y + 2x - 3)(x^2+(y-3)^2-0.035)((x-2)^2+(y+1)^2-0.035)=0 [-10, 10, -5, 5]}

How do you graph y=−2x+3y= -2x+3?