How do you graph $y = 3 sin (2x-2)$ ?

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Answer 1 · 2018-07-04T01:51:26

As below

Sine function format is $y = A sin( Bx - C) + D$

$y = 3 sin (2x - 2)$

$A = 3, B = 2, C = 2, D = 0$

$Amplitude = |A| = 3$

$"Period " = (2pi) / |B| = (2pi)/2 = pi$

$"Phase Shift " = -C / B = -2/2 = -1, color(crimson)(1" to the LEFT"$

$"Vertical Shift " = D = 0$

graph{3 sin (2x - 2) [-10, 10, -5, 5]}

How do you graph y = 3 sin (2x-2)y = 3 sin (2x-2)?