How do you graph #y = 3 sin (2x-2)#?

Question

1793 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-04T01:51:26

As below

Sine function format is #y = A sin( Bx - C) + D#

#y = 3 sin (2x - 2)#

#A = 3, B = 2, C = 2, D = 0#

#Amplitude = |A| = 3#

#"Period " = (2pi) / |B| = (2pi)/2 = pi#

#"Phase Shift " = -C / B = -2/2 = -1, color(crimson)(1" to the LEFT"#

#"Vertical Shift " = D = 0#

graph{3 sin (2x - 2) [-10, 10, -5, 5]}