How do you graph #y= 3 sin(pi*x/2)#?

1 Answer
Bdub
Mar 1, 2016

#A=3, B=pi/2, C=0, D=0, P=(2pi)/B=(2pi)/((pi)/2)=4#
#UB=3,LB=-3, Increments=P/4=1#

Explanation:

To graph draw the axis and your middle axis is the x-axis since C=0. From the x-axis go up 3 and go down 3 units then draw your highest and lowest or upper bound and lower bound. To sketch the graph you start from zero since D=0 and go in increments of 1 unit each time. Note that you only need five sinusoidal points to sketch one cycle but you can always continue your graph as it is going to infinity.

Related questions
See all questions in General Sinusoidal Graphs
Impact of this question
2179 views around the world
You can reuse this answer
Creative Commons License