How do you graph #y = 3cos(-2x + pi/2)#?

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Answer 1 · 2018-06-07T06:48:21

As below.

#y = A cos (Bx - C) + D# is the standard form

#y = 3 cos (-2x + pi/2)#

#A = 3, B = -2, C = pi/2, D = 0#

#Amplitude = |A| = 3#

#"Period " = (2pi)/|B| = (2pi) / 2 = pi#

#"Phase Shift " = -C / B = -(pi/2) / -2 = pi/4#, #color(red)(pi/4 " to the right"#

#"Vertical Shift " = 0#

graph{3 cos(pi/2 - 2x) [-10, 10, -5, 5]}