How do you graph #y=3log_2x#?

Question

3226 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-22T12:21:27

Socratic graph is inserted.

#y=3(log x/log 2),# using #log_b a=log a/log b#

#x>0#, to make the logarithm real.

The graph is inserted.

x-intercept ( y = 0 ): 1

As #x to oo, y to oo# and as #x to 0, y to -oo#.

See this logarithmic rise in the graph

graph{1/3y log 2- log x = 0 [-5, 5, -2.5, 2.5]}