How do you graph $y = - 3 sec (2 π x - \frac{π}{4})$ $y= - 3sec(2pix - pi/4)$ ?

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How do you graph $y = - 3 sec (2 π x - \frac{π}{4})$ $y= - 3sec(2pix - pi/4)$ ?

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Answer 1 · 2018-05-06T11:44:51

As below.

Explanation:

$y = A sec (B x - C) + D$ $y = A sec (Bx - C) + D$

$Given : y = - 3 sec (2 π x - (\frac{π}{4}))$ $"Given : " y = -3 sec (2pix - (pi/4))$

$Function : sec (x) doesn't have amplitude$ $"Function : sec (x) doesn't have amplitude"$

$Period = \frac{2 π}{| B |} = \frac{2 π}{2 π} = 1$ $"Period " = (2pi) / |B| = (2pi) / (2pi) = 1$

$Phase Shift = - \frac{C}{B} = \frac{\frac{π}{4}}{2 π} = \frac{1}{8}, 1/8 to the right$ $"Phase Shift " = -C / B = (pi/4) / (2pi) = 1/8, " 1/8 to the right"$

$Vertical Shift = D = 0$ $"Vertical Shift " = D = 0$

graph{-3 sec (2pix - (pi/4)) [-10, 10, -5, 5]}

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How do you graph $y = - 3 sec (2 π x - \frac{π}{4})$ $y= - 3sec(2pix - pi/4)$ ?

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