How do you graph $y = - 3 sec (\frac{π}{2} x)$ $y=-3sec(pi/2x)$ ?

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How do you graph $y = - 3 sec (\frac{π}{2} x)$ $y=-3sec(pi/2x)$ ?

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Answer 1 · 2016-11-28T07:13:03

The period of the graph is 4. Look for graph $x \in [0, 4]$ $x in [0, 4]$ , sans the points oh infinite discontinuity at x = 1 and x = 3, for the part of the graph, for one period.

Explanation:

sec (odd multiple of $\frac{π}{2}$ $pi/2$ ) = $\pm \infty$ $+-oo$ .

The period for the graph is

the period for #cos (pi/2x) = (2pi)/(pi/2) = 4.

$y = \pm 3$ $y = +-3$ , alternately, when x = an even integer.

$y \to \pm \infty$ $y to +-oo$ , as $x \to$ $x to$ an odd integer.

graph{ycos(pi/2x)+3=0 [-20, 20, -10, 10]}

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How do you graph $y = - 3 sec (\frac{π}{2} x)$ $y=-3sec(pi/2x)$ ?

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How do you graph y=−3sec(π2x)y=-3sec(pi/2x)?

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Explanation:

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How do you graph $y = - 3 sec (\frac{π}{2} x)$ $y=-3sec(pi/2x)$ ?