How do you graph $y = 3 x - 2$ $y = 3x - 2$ ?

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Answer 1 · 2015-06-13T23:01:06

This is a straight line of slope 3 which intercepts the $y$ $y$ axis at $(0, - 2)$ $(0, -2)$ and the $x$ $x$ axis at $(\frac{2}{3}, 0)$ $(2/3, 0)$

Equations of the form:

$y = m x + c$ $y = mx+c$

are the equations of lines in slope-intercept form, where $m$ $m$ is the slope of the line and $c$ $c$ is the intercept with the $y$ $y$ axis.

In your example, slope $m = 3$ $m=3$ and intercept $c = - 2$ $c=-2$ .

We can also determine where the line intersects the $x$ $x$ axis by solving for $x$ $x$ in the case $y = 0$ $y = 0$ ...

If $3 x - 2 = 0$ $3x-2 = 0$ then $3 x = 2$ $3x=2$ and $x = \frac{2}{3}$ $x=2/3$

graph{3x-2 [-10, 10, -5, 5]}

How do you graph y=3x−2y = 3x - 2?