How do you graph $y = - 3 x - 3$ $y=-3x-3$ ?

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Answer 1 · 2015-07-06T21:29:57

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The blue line on the graph.

We want to draw $y = - 3 x - 3$ $y=-3x-3$

Your equation is a linear equation because you can find 2 integers $a$ $a$ and $b$ $b$ such as : $y = a \cdot x + b$ $y = a*x+b$

(Here $a = - 3$ $a=-3$ and $b = - 3$ $b=-3$ )

The representative curve of a linear equation is a straight line!

As you know, we need only 2 points to draw a straight line.

We have to choose 2 points on our equation :

For example $A (- 1, f (- 1))$ $A(-1,f(-1))$ and $B (0, f (0))$ $B(0,f(0))$

$f (- 1) = - 3 \cdot (- 1) - 3 = 3 - 3 = 0$ $f(color(red)(-1))=-3*(color(red)(-1))-3 = 3 - 3 = 0$

$f (0) = - 3 \cdot (0) - 3 = 0 - 3 = - 3$ $f(color(red)(0))=-3*(color(red)(0))-3 = 0 - 3 = -3$

Now, we know the coordinates of $A$ $A$ and $B$ $B$ :
$A (- 1, 0), B (0, - 3)$ $A(-1,0) , B(0,-3)$

Spot $A$ $A$ and $B$ $B$ on the graph, and draw the straight line passing by this two points.

How do you graph y=−3x−3y=-3x-3?