How do you graph $y = - 4 x + 3$ $y=-4x+3$ ?

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Answer 1 · 2018-06-01T02:31:58

Refer to the explanation.

Graph:

$y = - 4 x + 3$ $y=-4x+3$

Convert the equation in slope-intercept form to standard form, $A x + B y = C$ $Ax+By=C$ , by adding $4 x$ $4x$ to both sides.

$4 x + y = 3$ $4x+y=3$

You only need two points to draw a straight line. Find the x- and y-intercepts.

X-intercept: value of $x$ $x$ when $y = 0$ $y=0$

Substitute $0$ $0$ for $y$ $y$ and solve for $x$ $x$ .

$4 x + 0 = 3$ $4x+0=3$

$4 x = 3$ $4x=3$

Divide both sides by $4$ $4$ .

$x = \frac{3}{4}$ $x=3/4$

The point for the x-intercept is $(\frac{3}{4}, 0)$ $(3/4,0)$ .

Y-intercept: value of $y$ $y$ when $x = 0$ $x=0$ .

Substitute $0$ $0$ for $x$ $x$ and solve for $y$ $y$ .

$4 (0) + y = 3$ $4(0)+y=3$

$0 + y = 3$ $0+y=3$

$y = 3$ $y=3$

The point for the y-intercept is $(0, 3)$ $(0,3)$ .

Plot the x- and y-intercepts and draw a straight line through them.

graph{4x+y=3 [-10, 10, -5, 5]}

How do you graph y=−4x+3y=-4x+3?