Question

How do you graph `y=4x+3` using slope intercept form?

Answer 1

1. Put a point at the y-intercept on the graph: `(0,3)`

2. Move up `4` points in the `+y`-direction and move `1` point in the `+x`-direction and place a second point.

Explanation:

Slope intercept form: `y = mx + b`

where `m = "slope" = (Delta y)/(Delta x) = (y_2 - y_1)/(x_2 - x_1)`

and `b = y-"intercept": (0, b)`

1. Put a point at the y-intercept on the graph: `(0,3)`

2. Slope = `4 = 4/1 = (-4)/-1`

3. Move up `4` points in the `+y`-direction and move `1` point in the `+x`-direction and place a second point.

4. Draw a line that passes through the two points

graph{4x + 3 [-12.18, 10.32, -2.475, 8.775]}