Question

How do you graph `y=-5/2x-3` using slope and intercept?

Answer 1

`"see explanation"`

Explanation:

`"the equation of a line in "color(blue)"slope-intercept form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))`

`"where m represents the slope and b the y-intercept"`

`y=-5/2x-3" is in this form"`

`rArr"slope "=-5/2" and y-intercept "=-3`

`"plot the point "(0,-3)`

`m=-5/2` slopes downwards from left to right 5 units vertically and 2 units horizontally from point to point.

`"from "(0,-3)` move 5 units up and 2 units left to obtain the point
`(-2,2)`

Or move 5 units down and 2 units right to obtain `(2,-8)`

`"plot these points and draw a straight line through them"`
graph{(y+5/2x+3)((x-0)^2+(y+3)^2-0.04)((x+2)^2+(y-2)^2-0.04)((x-2)^2+(y+8)^2-0.04)=0 [-20, 20, -10, 10]}