How do you graph $y = 5 csc 3 (x - π) - 5$ $y=5csc3(x-pi)-5$ ?

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Answer 1 · 2018-06-24T03:13:30

As below.

$y = 5 csc (3 x - 3 π) - 5$ $y = 5 csc (3x - 3pi) - 5$

Standard form of cosecant function is $y = A csc (B x - C) + D$ $y = A csc(Bx - C) + D$

$A = 5, B = 3, C = 3 π, D = - 5$ $A = 5, B = 3, C = 3 pi, D = -5$

$A m p l i t u d e = | A | = NONE for cosecant function$ $Amplitude = |A| = "NONE for cosecant function"$

$Period = \frac{2 π}{| B |} = \frac{2 π}{3}$ $"Period " = (2pi) / |B| = (2pi) / 3$

$Phase Shift = - \frac{C}{B} = \frac{3 π}{3} = π, π to the RIGHT$ $"Phase Shift " = -C / B = (3pi) / 3 = pi, " " pi " to the RIGHT"$

$Vertical Shift = D = - 5$ $"Vertical Shift " = D = -5$

graph{5 csc(3x - 3 pi) - 5 [-10, 10, -5, 5]}

How do you graph y=5csc3(x−π)−5y=5csc3(x-pi)-5?