How do you graph $y = - 5 x + 10$ $y=-5x+10$ using intercepts?

Question

4234 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-09-28T14:31:36

See a solution process below:

First, find the $y$ $y$ -intercept by setting $x$ $x$ to $0$ $0$ and calculating $y$ $y$ :

y-intercept:

$y = (- 5 \cdot 0) + 10$ $y = (-5 * 0) + 10$

$y = 0 + 10$ $y = 0 + 10$

$y = 10$ $y = 10$ or $(0, 10)$ $(0, 10)$

Next, find the $x$ $x$ -intercept by setting $y$ $y$ to $0$ $0$ and solving for $x$ $x$ :

x-intercept:

$0 = - 5 x + 10$ $0 = -5x + 10$

$0 - 10 = - 5 x + 10 - 10$ $0 - color(red)(10) = -5x + 10 - color(red)(10)$

$- 10 = - 5 x + 0$ $-10 = -5x + 0$

$- 10 = - 5 x$ $-10 = -5x$

$\frac{- 10}{- 5} = \frac{- 5 x}{- 5}$ $(-10)/color(red)(-5) = (-5x)/color(red)(-5)$

$2 = (color(red)(cancel(color(black)(-5)))x)/cancel(color(red)(-5))$

$2 = x$

$x = 2$ or $(2, 0)$

We can next graph the two points on the coordinate plane:

graph{(x^2+(y-10)^2-0.125)((x-2)^2+y^2-0.125)=0 [-25, 25, -12.5, 12.5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y+5x-10)(x^2+(y-10)^2-0.125)((x-2)^2+y^2-0.125)=0 [-25, 25, -12.5, 12.5]}

How do you graph y=-5x+10y=−5x+10y=-5x+10 using intercepts?