How do you graph $y=(5x+2)/(4x)$ using asymptotes, intercepts, end behavior?

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Answer 1 · 2017-02-19T09:17:36

Asymptotes : $x(y-5/4)=0$ . x-intercept ( y = 0 ) : $-2/5$ . No intercepts at all. See asymptotes-inclusive Socratic graph.

graph{(x(y-5/4)-1/2)(y-5/4+.001x) (x--.001y)=0 [-5, 5, -2.5, 2.5]}

This is $y = 5/4+1/(2x)$ , giving

$(y-5/4)(x)=1/2$ , representing the rectangular hyperbola,

with center at C( 0, 15/4) , at which the asymptotes

$x(y-5/4)=0$ intersect.

x-intercept ( y = 0 ) : $-2/5$

There are no intercepts at all.

How do you graph y=(5x+2)/(4x)y=(5x+2)/(4x) using asymptotes, intercepts, end behavior?