Question

How do you graph `y=cot(2x-pi/2)`?

Answer 1

See explanation and graph

Explanation:

`y = cot ( 2 x - pi/2 ) = - cot ( pi/2 - 2 x ) = - tan 2 x,`

`x ne` ( the asymptotic zero of the denominator sin 2x ) `k/2pi`.

k = 0, +-1, +-2, +_3, ...#

The period`= pi/2`.

The axis is y = 0.

The infinite-arm wave amplitude `= 1/2 ( pi/2 ) = pi/4`. See graph.
graph{(y+tan (2x))(y+0x)=0[-pi/2 pi/2 -pi/4 pi/4 ] }