How do you graph $y=cot(2x-pi/2)$ ?

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Answer 1 · 2018-08-13T01:28:28

See explanation and graph

$y = cot ( 2 x - pi/2 ) = - cot ( pi/2 - 2 x ) = - tan 2 x,$

$x ne$ ( the asymptotic zero of the denominator sin 2x ) $k/2pi$ .

k = 0, +-1, +-2, +_3, ...#

The period $= pi/2$ .

The axis is y = 0.

The infinite-arm wave amplitude $= 1/2 ( pi/2 ) = pi/4$ . See graph.
graph{(y+tan (2x))(y+0x)=0[-pi/2 pi/2 -pi/4 pi/4 ] }

How do you graph y=cot(2x-pi/2) y=cot(2x-pi/2)?