How do you graph $y = - cot (π \cdot x)$ $y = -cot (pi*x)$ ?

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Answer 1 · 2018-06-24T03:26:30

As seen below.

$y = (-) cot (π x)$ $y = (-) cot (pi x)$

Standard form of cotangent function is $y = A cot (B x - C) + D$ $y = A cot(Bx - C) + D$

$A = - 1, B = π, C = D = 0$ $A = -1, B = pi, C = D = 0$

$A m p l i t u d e = | A | = NONE for cotangent function$ $Amplitude = |A| = "NONE for cotangent function"$

$Period = \frac{π}{| B |} = \frac{π}{π} = 1$ $"Period " = (pi) / |B| = pi / pi = 1$

$Phase Shift = - \frac{C}{B} = 0$ $"Phase Shift " = -C / B = 0$

$Vertical Shift = D = 0$ $"Vertical Shift " = D =0$

graph{- cot(pix) [-10, 10, -5, 5]}

How do you graph y=−cot(π⋅x)y = -cot (pi*x)?