How do you graph $y = csc x + 3$ $y=cscx+3$ ?

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Answer 1 · 2018-05-06T11:38:53

As detailed.

Standard form of cosecant function is $y = A csc (B x - C) + D$ $y = A csc (Bx - C) + D$

$y = csc x + 3$ $y = csc x + 3$
$Function csc (x) doesn't have amplitude$ $"Function csc (x) doesn't have amplitude"$

$Period = \frac{2 π}{| B |} = \frac{2 π}{1} = 2 π$ $"Period " = (2pi) / |B| = (2pi) / 1 = 2pi$

#"Vertical Shift " = D = 3

$Phase Shift = - \frac{C}{B} = 0$ $"Phase Shift " = -C / B = 0$

graph{csc x + 3 [-10, 10, -5, 5]}

How do you graph y=cscx+3y=cscx+3?