Question

How do you graph `y=log_4(x-7)+9`?

Answer 1

This is a trick that is really worth committing to memory

Explanation:

General case: `" "log_a(x) =log_b(x)/log_b(a)`

So `y=log_4(x-7)+9` is the same as:

`y=log_10(x-7)/log_10(4)+9`