How do you graph y=sin1(x2) over the interval 1x3?

1 Answer
Dec 22, 2017

Please see below.

Explanation:

As y=sin1x means x=siny, the graph is similar to graph of y=sinx but wave is formed along y-axis. The range of y=sin1x is, however, [π2,π2] and hence its graph is limited between [π2,π2] along y-axis and corresponding values of x ranges from [1,1],

other values are (1,π2),(32,π3),(12,π4),(12,π6),(0,0),(12,π6),(12,π4),(32,π3),(1,π2).

The graph appears as follows:

graph{arcsinx [-10, 10, -5, 5]}

However, in y=sin1(x2) x can take values from [1,3] and hence the graph is similar to that of y=sin1x but shifted 2 units to right. The graph appears as follows:

graph{arcsin(x-2) [-10, 10, -5, 5]}