How do you graph #y < x^2 + 4x#?
1 Answer
Jun 15, 2017
First consider the equation
Note that this has zeros when
The vertex of this parabola will be halfway between the zeros, at
So, we can easily draw the parabola with the points
graph{x^2+4x [-14.09, 8.41, -5.855, 5.395]}
We want to find when
graph{y < x^2+4x [-14.09, 8.41, -5.855, 5.395]}