How do you graph $y = - x + 4$ $y=-x +4$ by plotting points?

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Answer 1 · 2018-03-24T00:37:59

Answer below.

The y-intercept is 4 so you graph the point (0,4).

When $x = 0$ $x=0$ ,

$y = - (0) + 4$ $y=-(0)+4$

$y = 4$ $y=4$

Next, you know the slope is $- x$ $-x$ , which is also $\frac{- 1}{1} x$ $(-1)/1x$ , so you

would go down 1 unit and right 1 unit on the graph. This method is

using $\frac{r i s e}{r u n}$ $(rise)/(run)$ . Then plot the points using the slope.

$O r$ $color(blue)(Or)$ you can find the points algebraically,

When $x = 1$ $x=1$ ,

$y = - (1) + 4$ $y=-(1)+4$

$y = 3$ $y=3$

When $x = 2$ $x=2$ ,

$y = - (2) + 4$ $y=-(2)+4$

$y = 2$ $y=2$

$and so on.$ $"and so on."$

graph{-x+4 [-10, 10, -5, 5]}

How do you graph y=−x+4y=-x +4 by plotting points?