How do you identify all asymptotes or holes and intercepts for $f (x) = \frac{1 - x^{3}}{x}$ $f(x)=(1-x^3)/x$ ?

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Answer 1 · 2016-11-10T10:53:38

A vertical asymptote is $x = 0$ $x=0$
The intercept with the x-axis is $(1, 0)$ $(1,0)$

As you cannot divide by $0$ $0$ , a vertial asymptote is $x = 0$ $x=0$

$lim_(x->+-oo)f(x)=lim_(x->+-oo)(-x^2)=-oo$

Intercepts, when $y=0$ $=>$ $x=1$
Therefore the intercept is $(1,0)$

graph{(1-x^3)/x [-14.24, 14.24, -7.11, 7.12]}

How do you identify all asymptotes or holes and intercepts for f(x)=(1-x^3)/xf(x)=1−x3xf(x)=(1-x^3)/x?