How do you identify all asymptotes or holes and intercepts for f(x)=x/(3x^2+5x)?

1 Answer
Jan 26, 2018

"see explanation"

Explanation:

"factorise the denominator"

f(x)=cancel(x)/(cancel(x)(3x+5))=1/(3x+5)

"since the factor x has been cancelled from the numerator/"
"denominator this indicates a hole at"(0,1/5)

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non-zero for this value then it is a vertical asymptote.

"solve "3x+5=0rArrx=-5/3" is the asymptote"

"horizontal asymptotes occur as"

lim_(xto+-oo),f(x)toc" ( a constant)"

"divide numerator/denominator by x"

f(x)=(1/x)/((3x)/x+5/x)=(1/x)/(3+5/x)

"as "xto+-oo,f(x)to0/(3+0)

rArry=0" is the asymptote"
graph{1/(3x+5) [-10, 10, -5, 5]}