How do you identify all asymptotes or holes and intercepts for f(x)=x/(3x^2+5x)?
1 Answer
Jan 26, 2018
Explanation:
"factorise the denominator"
f(x)=cancel(x)/(cancel(x)(3x+5))=1/(3x+5)
"since the factor x has been cancelled from the numerator/"
"denominator this indicates a hole at"(0,1/5) The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non-zero for this value then it is a vertical asymptote.
"solve "3x+5=0rArrx=-5/3" is the asymptote"
"horizontal asymptotes occur as"
lim_(xto+-oo),f(x)toc" ( a constant)"
"divide numerator/denominator by x"
f(x)=(1/x)/((3x)/x+5/x)=(1/x)/(3+5/x)
"as "xto+-oo,f(x)to0/(3+0)
rArry=0" is the asymptote"
graph{1/(3x+5) [-10, 10, -5, 5]}