How do you identify all asymptotes or holes for y=(4x^3+32)/(x+2)?

1 Answer
Nov 3, 2016

The function is a parabola

Explanation:

Let's do the long division
color(white)(aaaa)4x^3color(white)(aaaaaaaaaaa)+32x+2
color(white)(aaaa)4x^3+8x^2color(white)(aaaaaaaaa)4x^2-8x+16
color(white)(aaaaaa)0-8x^2
color(white)(aaaaaaaa)-8x^2-16x
color(white)(aaaaaaaa)-8x^2-16x
color(white)(aaaaaaaaaaaa)0+16x+32
color(white)(aaaaaaaaaaaaaa)+16x+32
color(white)(aaaaaaaaaaaaaaaa)+0+0

The result is (4x^3+32)/(x+2)=4x^2-8x+16
=4(x^2-2x+4)=4(x-2)^2
This is a parabola
graph{4(x-2)^2 [-25.65, 25.67, -12.83, 12.84]}