How do you identify the center and radius of the circle #(x-1)^2+y^2=10#?

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Answer 1 · 2018-04-07T21:56:51

Center: #(1,0)# Radius: #sqrt10#

The standard equation of a circle with center #(h,k)# and radius #r# is

#(x-h)^2+(y-k)^2=r^2#

Examining

#(x-1)^2+y^2=10,#

we see we really just have

#(x-1)^2+(y-0)^2=10^2#, making the center

#(1, 0)# and the radius #r^2=10 -> r=sqrt10#