How do you identify the oblique asymptote of $f(x) = (x^2+6x-9)/(x-2)$ ?

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Answer 1 · 2018-05-02T14:32:55

Below

$f(x)=(x^2+6x-9)/(x-2)$

$f(x)=((x-2)(x+8)+7)/(x-2)$

$f(x)=(x+8)+7/(x-2)$

Therefore, the oblique asymptote is $y=x+8$ and the vertical asymptote is $x=2$

graph{(x^2+6x-9)/(x-2) [-10, 10, -5, 5]}

How do you identify the oblique asymptote of f(x) = (x^2+6x-9)/(x-2)f(x) = (x^2+6x-9)/(x-2)?