2=e^(x-y)-frac{x}{cosy}2=ex−y−xcosy
0=(1-dy/dx)e^(x-y)-frac{cosy+xsiny(dy/dx)}{cos^2y}0=(1−dydx)ex−y−cosy+xsiny(dydx)cos2y
0=e^(x-y)-e^(x-y)(dy/dx)-secy-(xsiny)/cos^2y (dy/dx)0=ex−y−ex−y(dydx)−secy−xsinycos2y(dydx)
0=dy/dx(-e^(x-y)-(xsiny)/cos^2y)+e^(x-y)-secy0=dydx(−ex−y−xsinycos2y)+ex−y−secy
dy/dx(e^(x-y)+(xsiny)/cos^2y)=e^(x-y)-secydydx(ex−y+xsinycos2y)=ex−y−secy
dy/dx = frac{e^(x-y)-secy}{(e^(x-y)+(xsiny)/cos^2y)}dydx=ex−y−secy(ex−y+xsinycos2y)
dy/dx = frac{(cos^2y)(e^(x-y))-cosy}{(cos^2y)(e^(x-y))+xsiny}dydx=(cos2y)(ex−y)−cosy(cos2y)(ex−y)+xsiny
This fraction could be manipulated more to make terms cancel (eg multiplying by the conjugate of the denominator, etc.), but I have isolated dy/dxdydx.
