How do you implicitly differentiate $3 x^{2} - 2 x y + y^{2} = 11$ $3x^2 - 2xy + y^2 = 11$ ?

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How do you implicitly differentiate $3 x^{2} - 2 x y + y^{2} = 11$ $3x^2 - 2xy + y^2 = 11$ ?

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Answer 1 · 2016-02-14T18:20:13

$\frac{d y}{d x} = \frac{3 x - y}{x - y}$ $dy/dx=(3x-y)/(x-y)$

Explanation:

Start by taking the derivative on both sides of the equation with respect to $x$ $x$ , bearing in mind that $y$ $y$ is a function of $x$ $x$ .
Then solve for $\frac{d y}{d x}$ $dy/dx$ .

$therefore d/dx(3x^2-2xy+y^2)=d/dx11$

$therefore 6x-2xdy/dx-2y+2ydy/dx=0$

$thereforedy/dx=(6x-2y)/(2x-2y)$

$=(2(3x-y))/(2(x-y))$

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How do you implicitly differentiate $3 x^{2} - 2 x y + y^{2} = 11$ $3x^2 - 2xy + y^2 = 11$ ?

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Explanation:

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Science

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How do you implicitly differentiate 3x^2 - 2xy + y^2 = 11 3x2−2xy+y2=11 3x^2 - 2xy + y^2 = 11 ?

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Explanation:

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How do you implicitly differentiate $3 x^{2} - 2 x y + y^{2} = 11$ $3x^2 - 2xy + y^2 = 11$ ?