How do you implicitly differentiate #x^2 + y^2 = 1/2 #?
2 Answers
Jun 22, 2018
Explanation:
Jun 22, 2018
Explanation:
#color(blue)"differentiate implicitly with respect to x"#
#"noting that "d/dx(y^2)=2ydy/dx#
#2x+2ydy/dx=0#
#2ydy/dx=-2x#
#dy/dx=-(2x)/(2y)=-x/y#