How do you implicitly differentiate #-y^2=xy^3-x^4y #?
1 Answer
May 16, 2016
Given -
#-y^2=xy^3-x^4y#
#-2ydy/dx=[x.3ydy/dx+y^3 . 1]-[x^4dy/dx+y.4x^3]#
#-2ydy/dx=3xydy/dx+y^3-x^4+4x^3y#
#-2ydy/dx-3xydy/dx=y^3-x^4+4x^3y#
#-(2y+3xy)dy/dx=y^3-x^4+4x^3y#
#-y(2+3x)dy/dx=y^3-x^4+4x^3y#
#dy/dx=(y^3_x^4+4x^3y)/(-y(2+3x)#