How do you insert parentheses to make $2^{3} - 3 \cdot 5 - 8 = 1$ $2^3 -3*5-8=1$ true?

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Answer 1 · 2018-03-30T15:01:49

$2^{3} - (3 \cdot 5 - 8) = 1$ $2^3-(3*5 - 8) =1$

By the order of operations, $(3 \cdot 5 - 8) = 7$ $(3*5 - 8) = 7$

$2^{3} = 8$ $2^3 = 8$ , so 8 - 7 = 1

How do you insert parentheses to make 23−3⋅5−8=12^3 -3*5-8=1 true?