How do you integrate $\frac{1}{2 x + 1}$ $1/(2x+1)$ ?

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How do you integrate $\frac{1}{2 x + 1}$ $1/(2x+1)$ ?

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Answer 1 · 2017-01-08T03:23:05

$\int \frac{d x}{2 x + 1} = \frac{1}{2} ln | 2 x + 1 | + C$ $int (dx)/(2x+1) = 1/2 ln abs (2x+1)+C$

Explanation:

$\int \frac{d x}{2 x + 1} = \frac{1}{2} \int \frac{d (2 x + 1)}{2 x + 1} = \frac{1}{2} ln | 2 x + 1 | + C$ $int (dx)/(2x+1) = 1/2 int (d(2x+1))/(2x+1) = 1/2 ln abs (2x+1)+C$

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How do you integrate $\frac{1}{2 x + 1}$ $1/(2x+1)$ ?

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