How do you integrate 1/(xlnx)dx1xlnxdx?

1 Answer
Feb 15, 2015

Hello !

I propose another solution.

Remember that (\ln(u))' = \frac{u'}{u} if u is a positive differentiable function.

Take u (x) = \ln(x) for x>1 : it's a positive differentiable function.

Remark that \frac{u'(x)}{u(x)} = \frac{\frac{1}{x}}{\ln(x)} = \frac{1}{x\ln(x)}, then

\int \frac{\text{d}x}{x\ln(x)} = \ln(u(x)) + c = \ln(\ln(x)) + c,

where c is a real constant.