Question

How do you integrate `e^(2x)`?

Answer 1

Take its derivative first hence

`(e^(2x))'=e^(2x)*2=>e^(2x)=1/2(e^(2x))'`

Hence

`int e^(2x)dx=int 1/2*(e^(2x))'dx=e^(2x)/2+c`