How do you integrate #f(x)=x^3-3x-2x^-4# using the power rule? Calculus Basic Differentiation Rules Power Rule 1 Answer sjc Nov 18, 2016 #1/4x^4-3/2x^2+2/3x^-3+C# Explanation: for polynomials #intx^ndx=x^(n+1)/(n+1)+C,n!=-1# #int(x^3-3x-2x^(-4))dx# #=x^(3+1)/(3+1)-3x^(1+1)/(1+1)-2x^(-4+1)/(-4+1)+C# #=x^4/4-(3x^2)/2-(2x^-3)/-3+C# tidying up #1/4x^4-3/2x^2+2/3x^-3+C# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 1248 views around the world You can reuse this answer Creative Commons License