How do you integrate $h(s)=s^(4/5)$ using the power rule?

Question

1674 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-20T20:30:56

See below.

The power rule for integration is the opposite of the power rule for differentiation.

For integrals we have: $int x^n dx = 1/(n+1) x^(n+1) +C$ for $n != -1$ .

So

$int s^(4/5) ds = 1/(4/5+1) s^(4/5+1) +C$

Or, quicker using $4/5+1 = 9/5$ and $1/(9/5) = 5/9$ ,

$int s^(4/5) ds = 5/9s^(9/5) +C$

How do you integrate h(s)=s^(4/5)h(s)=s^(4/5) using the power rule?