Question

How do you integrate `int(3-x)^10 dx`?

Answer 1

Hello,

Consider `F(x) = - (3-x)^(11)/11`. So, `F'(x) = (3-x)^(10)`. Therefore,

`int (3-x)^(10) dx = - (3-x)^(11)/11 + c`

where `c in RR` is an arbitrary constant.