How do you integrate $\int {(3 - x)}^{10} d x$ $int(3-x)^10 dx$ ?

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Answer 1 · 2015-02-23T23:25:56

Hello,

Consider $F (x) = - \frac{{(3 - x)}^{11}}{11}$ $F(x) = - (3-x)^(11)/11$ . So, $F'(x) = (3-x)^(10)$ . Therefore,

$int (3-x)^(10) dx = - (3-x)^(11)/11 + c$

where $c in RR$ is an arbitrary constant.

How do you integrate int(3-x)^10 dx∫(3−x)10dxint(3-x)^10 dx?