How do you integrate $int e^(1/t)/t^2$ by parts?

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Answer 1 · 2016-11-27T05:24:10

Integration by parts is a waste of time. Just use the substitution $u=1/t$ . This implies that $du=-1/t^2dt$ .

$inte^(1/t)/t^2dt=-inte^(1/t)(-1)/t^2dt=-inte^udu=-e^u+C=-e^(1/t)+C$

How do you integrate int e^(1/t)/t^2int e^(1/t)/t^2 by parts?