Question

How do you integrate `int pisinpix dx`?

Answer 1

Using `u`-substitution, we will find a value in the function whose derivative will appear in the integrand.

Thus, we will let:

`u=pix`
`du=pidx`

So, if we plug it back in:

`=intsin(u)du`

`=-cos(u)+c`

`=-cos(pix)+c`